| NDT.net Dec 2004 Vol. 12 No.12 |
X rays linear attenuation coefficient in steel.
V. Dorobantu |
| I (X) = I0e µx | (1) |
where µ is called the linear attenuation factor, or absorption factor. Intensity I has the usual meaning, being the average of the Poynting vector S, namely
| I (X) = e0 c {Eµx} | (2) |
with e0, vacuum dielectric constant, c, light speed in vacuum, {Eµx} the average of the electric field squared. As one can see from the above expression for I, the entire process of absorption is contained in µ. Writing the refractive index [1] in the general form:
| n = n1 - i n2 | (3) |
where n1 and n2 are real numbers and i - imaginary number ( i2 = -1), only n2 is responsible for absorption.
| (4) |
where E0 and w are the electric field and the frequency of the incident electromagnetic wave. Comparing expressions (1) and (4) we have µ.
| (5) |
The aetiology of the X - rays' attenuation recalls, mainly, three aspects [2]:
| (6) |
where wj is the weight of the j - X ray component from the total number n. Taking the logarithm in (6), we will get an important result: the linear attenuation coefficient depends on thickness x.
In the above expression m is the number of terms we take in the series expansion. Further, if we take another series expansion of the natural logarithm in (8) we get:
| (10) |
where bk are coefficients depending on different µ's, and j is the number of terms we take in series expansion. Also, if we evaluate a1 from (9), we can get:
| (11) |
One can see from the above expression, that the linear attenuation coefficient of electromagnetic waves, of any kind, decreases with traversed thickness x. The coefficients, µaverage and bk , can be determined from experimental data.
| D = D0 eµx | (12) |
where D-film blackening density, D0 a quantity depending on the current of X ray source, on the film to source distance, exposure time t, and some constants which are characteristic to the film we use. Because of the thickness dependence of µ, we have different µ's on the defect and near it. Measuring the film densities on the defect (D1) and just near it (D2), see Fig. 1, then the ratio of the two D's is a function of the dimension of the defect, as well as of the entire thickness traversed by electromagnetic waves.
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The ratio:
| (13) |
where Dfog is the fog density. For µ as a function of the thickness x, we can use the expression (11) but it seems to be unpractical to get the dimension of the defect by solving an algebraic equation of a degree higher than two. As a consequence, is desirable to get a simpler function for µ instead of a polynomial. Such a function it was proved to be:
|
The problem is to find a and b with a reasonable approximation, so to be able to get a good (trusting) results for the dimension of the defect. We have measured blackening densities of the AGFA D7 film for different material thicknesses ( 3 - 28 mm), different accelerating voltages (120 - 240 kV), and different dimensions of defects ( 0.5 - 5.5 mm). Knowing the dimensions of the defects, we have got the a and b coefficients for µ(x). Here are some results. I have to mention that the results refer to wide X rays beam, namely without collimation, which, in fact, is the usual situation we deal with. Accelerating voltage U = 140 kV.
| (17) |
With this µ, the calculated dimensions of defects versus real dimensions looks like this:
Fig.2 |
The errors are well within 10% Accelerating voltage, U = 200 kV.
| (18) |
The calculated defects' dimensions versus real dimensions are:
Fig.3 |
In both cases, as well as in general, the defect's dimension is calculated solving the second degree equation resulting from (16). In the general case the solution is:
| (19) |
Here is a comparison of the experimental data [4],[5],our own, for µ, and the calculated, when U = 200 kV. The errors are within 6%.
Fig.4 |
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