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Technical Discussions
suresh kumar
Engineering, NDT LEVEL-3
NBTC, Kuwait, Joined Dec 2012, 19

suresh kumar

Engineering, NDT LEVEL-3
NBTC,
Kuwait,
Joined Dec 2012
19
11:54 Feb-16-2017
code case 181-2

how to apply code case 181-2 acceptance criteria?

h/t and h/l

example:

t=35mm
h=9mm subsurface
L=38mm

answer? can accept or reject? and how?

ngo tuong
NDT Inspector, PV EIC NDT
PV EIC NDT, Vietnam, Joined Mar 2014, 19

ngo tuong

NDT Inspector, PV EIC NDT
PV EIC NDT,
Vietnam,
Joined Mar 2014
19
09:32 Feb-20-2017
Re: code case 181-2
In Reply to suresh kumar at 11:54 Feb-16-2017 (Opening).

Dear Kumar
It is reject
- First caculate h/l = 9/38=0.236. See table 2 at ratio h/l with valuate 0.20 and next colum h/t is > or =0.086.This mean with h/l= 0.20 is unacceptale with any valuate > or = 0.086
- Second h/t = 9/35 =0.257 > 0.086 So reject
Regard,

suresh kumar
Engineering, NDT LEVEL-3
NBTC, Kuwait, Joined Dec 2012, 19

suresh kumar

Engineering, NDT LEVEL-3
NBTC,
Kuwait,
Joined Dec 2012
19
09:51 Feb-20-2017
Re: code case 181-2
In Reply to ngo tuong at 09:32 Feb-20-2017 .

THANK YOU

suresh kumar
Engineering, NDT LEVEL-3
NBTC, Kuwait, Joined Dec 2012, 19

suresh kumar

Engineering, NDT LEVEL-3
NBTC,
Kuwait,
Joined Dec 2012
19
09:53 Feb-20-2017
Re: code case 181-2
In Reply to suresh kumar at 09:51 Feb-20-2017 .

Pls clarify the following things also.

for below 25mm thickness , as per B31code case , we supposed to use ASME B31.3 Para 344.6.2

it states that,

344.6.2 Acceptance Criteria. A linear-type discontinuity
is unacceptable if the amplitude of the indication
exceeds the reference level and its length exceeds
(a) 6 mm (1⁄4 in.) for Tw ≤ 19 mm (3⁄4 in.)
(b) Tw/3 for 19 mm > Tw ≤ 57 mm (21⁄4 in.)
(c) 19 mm for Tw > 57 mm

what is linear indication?

if u say length is greater than 3 times of width phenomena, How to measure width in PAUT ?

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